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5k^2+k=0.4
We move all terms to the left:
5k^2+k-(0.4)=0
We add all the numbers together, and all the variables
5k^2+k-0.4=0
a = 5; b = 1; c = -0.4;
Δ = b2-4ac
Δ = 12-4·5·(-0.4)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-3}{2*5}=\frac{-4}{10} =-2/5 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+3}{2*5}=\frac{2}{10} =1/5 $
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